P(n)=-1/2n^3+96n+600 P= profit per week n=NUmber of worker find the number of workers that would give a maximum profit per week I don't understand what I do to find the answer for this? :S would anyone be able to help me?
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Differentiate P(n) with respect to n and find the local maxima. These points can be found by equating P'(n)=0. The n you get will give you the max profit.
Last edited by Ackbeet; June 6th 2011 at 02:14 AM. Reason: Correcting grammar, abbreviations.
thank you