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Math Help - Antiderivative of Log

  1. #1
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    Antiderivative of Log

    hi guys can you please help me with this:

    Find f given that f''= \frac{-3}{x^2} , f'(3) =5, and f(1) =3.

    I got this far:

    f'= \frac{3}{x} + 4

    f=3log(x)+ 4x + C = 3

    so log((1)^3) + 4(1) + C =3

    Am I on the right track? If so I don't quite know what to do next
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  2. #2
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    Yes, looks good. Remember that log(1) = 0. Evaluate C.
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  3. #3
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    Right! why do I keep forgetting these simple things

    3logx + 4x -1 Thanks!
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