hi guys can you please help me with this: Find f given that f''= , f'(3) =5, and f(1) =3. I got this far:
f=3log(x)+ 4x + C = 3
so log((1)^3) + 4(1) + C =3
Am I on the right track? If so I don't quite know what to do next
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Yes, looks good. Remember that log(1) = 0. Evaluate C.
Right! why do I keep forgetting these simple things
3logx + 4x -1 Thanks!