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Math Help - 1st and 2nd derivatives of y=e^(1/(x^2))

  1. #1
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    1st and 2nd derivatives of y=e^(1/(x^2))

    for the first derivative i got:

    y'=(-2e^1/(x^2)) /x^3

    2nd one i got:

    (4x^3e^1/(x^2) + 6x^2e^1/(x^2)) / x^6


    are they correct? if not, what are the correct answers...?

    thank you in advance
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  2. #2
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    Quote Originally Posted by LandLBoy View Post
    for the first derivative i got:

    y'=(-2e^1/(x^2)) /x^3

    2nd one i got:

    (4x^3e^1/(x^2) + 6x^2e^1/(x^2)) / x^6


    are they correct? if not, what are the correct answers...?

    thank you in advance
    Dear LandLBoy,

    The first derivative is correct. But the second derivative should be,

    \frac{d^{2}y}{dx^2}=\frac{4e^{\frac{1}{x^2}}+6x^{2  }e^{\frac{1}{x^2}}}{x^6}
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