# 1st and 2nd derivatives of y=e^(1/(x^2))

• Jun 4th 2011, 05:04 PM
LandLBoy
1st and 2nd derivatives of y=e^(1/(x^2))
for the first derivative i got:

y'=(-2e^1/(x^2)) /x^3

2nd one i got:

(4x^3e^1/(x^2) + 6x^2e^1/(x^2)) / x^6

are they correct? if not, what are the correct answers...?

• Jun 4th 2011, 08:03 PM
Sudharaka
Quote:

Originally Posted by LandLBoy
for the first derivative i got:

y'=(-2e^1/(x^2)) /x^3

2nd one i got:

(4x^3e^1/(x^2) + 6x^2e^1/(x^2)) / x^6

are they correct? if not, what are the correct answers...?

$\frac{d^{2}y}{dx^2}=\frac{4e^{\frac{1}{x^2}}+6x^{2 }e^{\frac{1}{x^2}}}{x^6}$