I have to differentiate the following:

$\displaystyle f(x)=\frac{2}{ 3x-2 }$

Alright simple enough so i follow the quotient rule for this question:

$\displaystyle f(x)=\frac{g(x)\cdot f'(x) - f(x)\cdot (g'(x)}{[g(x)]^2 } $

$\displaystyle \frac{(3x-2)(0)-(2)(3)}{(3x-2)^2 } $

$\displaystyle \frac{(3x-2)-6}{(3x-2)^2 }$

When i check the answer in mathway it says it should be :

$\displaystyle -\frac{6}{(3x-2)^2 } $

So not really sure about what happens to the 3x-2? is the question still right if you only get to:

$\displaystyle \frac{(3x-2)-6}{(3x-2)^2 }$