y = x(5-x)^2/3 i found y''(x)= (10x-60)/(9x-45)(5-x)^1/3 how would i set up my intervals for this to find concavity points?
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Originally Posted by LandLBoy y = x(5-x)^2/3 i found y''(x)= (10x-60)/(9x-45)(5-x)^1/3 how would i set up my intervals for this to find concavity points? See this
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