y = x(5-x)^2/3

i found y''(x)= (10x-60)/(9x-45)(5-x)^1/3

how would i set up my intervals for this to find concavity points?

Printable View

- June 2nd 2011, 04:56 PMLandLBoyConcavity of this function
y = x(5-x)^2/3

i found y''(x)= (10x-60)/(9x-45)(5-x)^1/3

how would i set up my intervals for this to find concavity points? - June 2nd 2011, 05:18 PMPlato