Thanks so much!
The first one, I have no clue and showing the steps/solution would help me understand the material.
For the second one I have this...
but am still stuck.
Thanks!!
Thanks so much!
The first one, I have no clue and showing the steps/solution would help me understand the material.
For the second one I have this...
but am still stuck.
Thanks!!
note that p(2) = 4a + 2b + c.
now, i'll bet you that when you differentiate p(x), you'll get an equation with only TWO variables when you find p'(2).
and then, when you find p"(x), maybe, just maybe, it will only involve ONE when you find p"(2).
but then, if you solve for that one variable, you can substitute in the equation you get for p'(2), and solve for another.
two variables down, and only 3 in p(2) = 3....shouldn't be too hard, then.....