A step in an integral question multiplying logs and fractions

I have a problem understanding a part of a solution to a calculus question. It's a 'by-parts' question and it's close to the solution.

= [ln2 (2^4/4)-(2^5/16)] - [-1/16]

I don't understand this next step:

=4ln2 (2^4/4(4)) - (2^5/16) + (1/16)

I understand that this part in red is being multiplied by 4 in order to get 16s in the denominators, but understand is how it's being multiplied by 4. Are the log and fraction together? How does (2^4/4)x4 become (2^4/4(4))?

Thanks for any help :)