Hi,

I have the follwing that I am struggling with:

\int sin^2(4t) cos(4t).dt

so far I have got:

u = sin^2(4t)

du/dt = 4t

du = 1/4

Now I am not sure what to do with the cos(4t) can someone help explain and show me the answewer so I maybe able to work backwards?

Thanks

m