Thread: Help with integral of (4sin(x-4))^2

1. Help with integral of (4sin(x-4))^2

I cant seem to figure out what the integral of this is correctly. If anyone can help it would be appreciated as i need the integral for part of a project.

Note: The entire function is squared, not just the (x-4).

Thanks

2. Well,

It could be written as : $16 \int sin^2(x-4) \, dx$. Right?

Substitute $u=x-4~.$ then use a trigonometry identity. Tell us what will you get.

3. Since $(4\sin(x-4))^2 = 16\sin^2(x-4)$ we can pull the 16 out front: $16 \int \sin^2(x-4)$ but to make it easier I'm going to write is at $8 \int 2\sin^2(x-4)$

You can then use a double angle identity: *edited out*