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Math Help - Help with integral of (4sin(x-4))^2

  1. #1
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    Help with integral of (4sin(x-4))^2

    I cant seem to figure out what the integral of this is correctly. If anyone can help it would be appreciated as i need the integral for part of a project.

    Note: The entire function is squared, not just the (x-4).

    Thanks
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  2. #2
    Ted
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    Well,

    It could be written as : 16 \int sin^2(x-4) \, dx. Right?

    Substitute u=x-4~. then use a trigonometry identity. Tell us what will you get.
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  3. #3
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    e^(i*pi)'s Avatar
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    Since (4\sin(x-4))^2 = 16\sin^2(x-4) we can pull the 16 out front: 16 \int \sin^2(x-4) but to make it easier I'm going to write is at 8 \int 2\sin^2(x-4)

    You can then use a double angle identity: *edited out*
    Last edited by e^(i*pi); May 28th 2011 at 01:33 PM. Reason: felt like I was giving too much info
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