Integral. #7

**TWiX** · May 27th 2011, 09:01 AM

If $\displaystyle \int_1^2 e^{t^2} \, dt = \alpha$

Evaluate ( in terms of $\displaystyle \alpha$ ) :

$\displaystyle \int_{e}^{e^4} \sqrt{ln (x)} \,\ dx$

**Amer** · May 27th 2011, 09:25 AM

sub
u^2 = ln (x) and change the limit of the integral

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