Nope. Try again (almost got it!!)
Hi everyone,
Can you please tell me if this is correct and if it isn't can you show me what I did wrong?
Find the interval:
y^3 square root of (2y^4-1)dy
u=2y^4-1
du=8y^3dy
y^3dy=du/8
y^3square root of 2y^4-1dy=
square root of u du/8=
square root of u/8=
u^(3/2)/9+c=
1/9(2y^4-1)^(3/2)+c
Thank you very much