Using the power rule: $\displaystyle y=0.0002{t}^{ 3} -0.4{t}^{ 2}+4+\frac{100}{{t}^{2 } } $ $\displaystyle y=0.0006{t}^{ 2}-0.8t-200{t}^{-3 } $ just trying to check my answer
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Originally Posted by purplec16 Using the power rule: $\displaystyle y=0.0002{t}^{ 3} -0.4{t}^{ 2}+4+\frac{100}{{t}^{2 } } $ $\displaystyle y=0.0006{t}^{ 2}-0.8t-200{t}^{-3 } $ just trying to check my answer You are correct purplec16.
Ok...thank you
Although, technically, you should write $\displaystyle \dot{y}$ or $\displaystyle y'$ for your derivative.
i did i just forgot to put it on the forum my apologies.
Last edited by Ackbeet; May 25th 2011 at 05:40 AM. Reason: Split new question into a new thread.
No problem!
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