# Find the derivative

• May 24th 2011, 06:05 PM
purplec16
Find the derivative
Using the power rule:

$y=0.0002{t}^{ 3} -0.4{t}^{ 2}+4+\frac{100}{{t}^{2 } }$

$y=0.0006{t}^{ 2}-0.8t-200{t}^{-3 }$

just trying to check my answer
• May 24th 2011, 06:21 PM
Sudharaka
Quote:

Originally Posted by purplec16
Using the power rule:

$y=0.0002{t}^{ 3} -0.4{t}^{ 2}+4+\frac{100}{{t}^{2 } }$

$y=0.0006{t}^{ 2}-0.8t-200{t}^{-3 }$

just trying to check my answer

You are correct purplec16.
• May 25th 2011, 04:28 AM
purplec16
Ok...thank you
• May 25th 2011, 04:48 AM
Ackbeet
Although, technically, you should write

$\dot{y}$ or $y'$