# Thread: Finding the derivative of the function

1. ## Finding the derivative of the function

$f(x)= \frac{{x}^{3 }-{4x}^{2 }+3 }{x }$

$f'(x)=\f{3x}^{2 }-8x +{x}^{ -2}$

I'm kinda confused on what happens to the x in the denominator i don't know if i should add it or multiply the numerator by it so that is the answer i felt most comfortable

2. There are two ways to solve it. Either write it as you have and use the quotient rule. Or you can simply use $f(x)=\frac{x^3-4x^2+3}{x}=x^2-4x+\frac{3}{x}$

3. I really dont understand how you got that answer

4. oh ok cool thanks...i understand what you did you divided each term by x

5. I just wrote f(x) in a different way using basic algebra. You should easily be able to differentiate the second form.

6. so is the answer $f'(x) = 2x-8x-{3x}^{-2 }$

7. Almost, but the second term is not right.

$f'(x)=2x-8-{3x}^{-2 }$
9. No. $\frac{d}{dx}\left(-4x\right) \neq -8$