I got the limit =
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When you use the definition, the limit will involve (depending on the form you use), the letter h, a, x_0, or delta x. You should have for starters, at least.
I have that, I'm trying to check my answer and that is where I got stuck I would type it all out but i'm extremely tired
Originally Posted by purplec16 I have that, I'm trying to check my answer and that is where I got stuck I would type it all out but i'm extremely tired For f(x) = 3/(2x + 1) f'(x) = -6/(2x + 1)^2 , which is what you have (after simplifying). You can check using wolfram... y = 3/(2x + 1) - Wolfram|Alpha
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