x=(sin^3)t/(sqrt(cos2t) and y=(cos^)3t/(sqrt(cos2t) y=(cot^3)t *x after that what should be donr
Follow Math Help Forum on Facebook and Google+
Personally, I would start with an actual problem statement. Are we converting to Cartesian Coordinates?
we have to find dy/dx
Originally Posted by prasum we have to find dy/dx $\displaystyle \frac{dy}{dx}=\frac{\frac{dy}{dt}}{\frac{dx}{dt}}= ...$ You do not need to convert just take the derivatives and use the above.
By the way, there is no such thing as (sin^3)t or (cos^3)t. You mean sin^3(t) and cos^3(t).
View Tag Cloud