x=(sin^3)t/(sqrt(cos2t) and y=(cos^)3t/(sqrt(cos2t)
after that what should be donr
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Personally, I would start with an actual problem statement. Are we converting to Cartesian Coordinates?
we have to find dy/dx
Originally Posted by prasum we have to find dy/dx
You do not need to convert just take the derivatives and use the above.
By the way, there is no such thing as (sin^3)t or (cos^3)t. You mean sin^3(t) and cos^3(t).
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