The length along the x-axis is going to be for some x. The length along the y-axis is .
That gives us the area to maximize.
I have absolutely no idea how to approach this question...
Draw a diagram showing the region enclosed between the parabola y^2=4ax and its latus rectum x=a
The, find the dimensions of the rectangle of max area that can be inscribed in this region.
I drew the diagram...but so far all i have for the area equation is A=2yx (y is doubled because the parabola extends below the axis as well XD)
Im having trouble uploading a picture, so ill describe the diagram...its a sideways parabola extending on the right side of the y axis, and the latus rectum cuts the x axis at "a" and the parabola when y= 2a and -2a
Basically, i have no idea what to do...could anyone help?