Originally Posted by

**Ned Hunter** hey this is a question i have for Year 12 Maths C in Australia. It is irritating me no end. **<line of text deleted by CaptainBlack>**

here we go...

A particle of mass one unit moves in a straight line in the horizontal plane against a resistance v+av^2 , where a is a positive constant. If v is the velocity of the particle at time t , then dv/dt=-(v+av^2) represents the particle’s motion.

Given this particle is released from the origin, O, with an initial velocity of u, find the velocity of the particle v as a function of the time t .

As the value of t increases, what happens to the velocity of this particle? Would this value change if a is negative?

PLEASE HELP! I WILL BE FOREVER IN YOUR DEBT. EMAIL ME OR RESPOND HERE, I WILL CHECK IT EVERY 30 MINUTES

THANKS