Ok so I am a little stuck on this question, I need to test this series using only the standard comparison test.

$\displaystyle \sum_{n = 2}^\infty \frac{\left\vert{\sin n } \right\vert{} }{{n}^{2 }-1}$

I can't compare it to $\displaystyle \frac{1}{{n}^{ 2}}$ can I?