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**Ackbeet** 2. I have a question: are you absolutely sure that you're supposed to maximize and minimize f(x) on the open interval (1,6)? That's what you've got there: 1 < x < 6. This function doesn't have a maximum value on that interval, though it does have a minimum value. If you meant the closed interval [1,6], with 1 <= x <= 6, then the function, being continuous on a closed interval, will have a maximum. In that case, you'd evaluate f at the critical point x = 4, and at the endpoints x = 1, and x = 6. What values of the function do you get for those three values?