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Math Help - Integral of 1/x^2

  1. #1
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    Integral of 1/x^2

    Hi there, I am here for some major help in the Advanced Aplied maths forum and thought this small question is better asked here.

    I have as part of a larger integral 1/x^2, the answer to which i believe to be -1/x. Could someone please explain to me how this is obtained?

    The entire integral if it is helpful is:

    \int^{2}_{1}(1/x^2 + cos x) dx
    Last edited by Alias_NeO; August 27th 2007 at 09:11 AM. Reason: found the int code.
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  2. #2
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    Polynomial or Exponent Rule?

    \frac{d}{dx}(-\frac{1}{x}) = \frac{d}{dx}(-x^{-1}) = -(-1)x^{-2} = \frac{1}{x^{2}}
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  3. #3
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    Thanks

    Thanks, that makes sense now, because there is so much math i don't know, i forget the simple things expecting it to be something more difficult, of course i was forgetting that

    \frac{1}{x^2} is the same as x^{-2}


    EDIT: What is the diff between the Plynomial and Exponent rules? I am unfamiliar with different rules for integrating things.
    Last edited by Alias_NeO; August 27th 2007 at 10:11 AM. Reason: EDIT:
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