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Math Help - integrals of quotients from a seperation problem

  1. #1
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    integrals of quotients from a seperation problem

    hi, im stuck on this question:

    dy/dx=\frac(xy+3x-y-3)/(xy-2y+4y-8)

    of which i got to [(y-2)/(y+3)] dy = [(x-1)/(x+4)] dx

    however from there i am having difficulty integrating both sides of the equation because frankly im not sure how to,

    any help would be appreciated,
    thanks.
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  2. #2
    MHF Contributor
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    Something funny in that denominator. I'll assume it's a typo and that you have separated it correctly.

    Would you believe Long Division?!

    \frac{y-2}{y+3}\;=\;1-\frac{5}{y+3}
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  3. #3
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    i completely forgot about long division!!! thank you
    and the 2x was supposed to be a 2y
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