hi, im stuck on this question:

dy/dx=\frac(xy+3x-y-3)/(xy-2y+4y-8)

of which i got to [(y-2)/(y+3)] dy = [(x-1)/(x+4)] dx

however from there i am having difficulty integrating both sides of the equation because frankly im not sure how to,

any help would be appreciated,

thanks.