# Math Help - integrals of quotients from a seperation problem

1. ## integrals of quotients from a seperation problem

hi, im stuck on this question:

dy/dx=\frac(xy+3x-y-3)/(xy-2y+4y-8)

of which i got to [(y-2)/(y+3)] dy = [(x-1)/(x+4)] dx

however from there i am having difficulty integrating both sides of the equation because frankly im not sure how to,

any help would be appreciated,
thanks.

2. Something funny in that denominator. I'll assume it's a typo and that you have separated it correctly.

Would you believe Long Division?!

$\frac{y-2}{y+3}\;=\;1-\frac{5}{y+3}$

3. i completely forgot about long division!!! thank you
and the 2x was supposed to be a 2y