I am just starting on the improper integral section. I am having trouble with this problem because I cannot seem to break it down easily into something that does not have (x-5) in the denominator. If I try to do lim R -> 5+, I will still get an undefined answer. I am doing something wrong, but I do not know what.

12. $\displaystyle \int^6_5 \frac{dx}{(x-5)^{3/2}}$

I get the general antiderivative, but I cannot get rid of the denominator, and since the numerator is just 1, I cannot use L'Hopital's Rule.

Thanks for your help.