hi,

I have this problem:

An electric elevator with a hoist motor at the top has a steel cable which weighs 2

kg per m. The total left hight of the elevator is 20 m from the basement to the top

floor. Assume that the cable is completely wound onto the motor when the elevator

is in the top floor position. Determine the total amount of work done in lifting a

500 kg load from the basement to the top floor. What should the power rating of

the motor be if this task is to be performed in 10 seconds (Give your answer in kW,

where 1 kW = 1000 J/s).

I don't really understand this :L