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Math Help - Differentiate a Function

  1. #1
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    Differentiate a Function

    i got given this question for home work and i have know idea where to start

    given that d sin(x)/dx = cos(x) use the chain rule to differentiate the function f(x)=+or-squre root of 1-sin squared(x) , pi/2<x<pi

    help would be much appreciated
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  2. #2
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    you know the identity

    sin^2x+cos^2x=1

    \Rightarrow cos^2x=1-sin^2x

    \Rightarrow cosx=\pm \sqrt{1-sin^2x}

    so your function will be f(x)=cosx
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  3. #3
    Senior Member bugatti79's Avatar
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    Quote Originally Posted by fuzzyx View Post
    i got given this question for home work and i have know idea where to start

    given that d sin(x)/dx = cos(x) use the chain rule to differentiate the function f(x)=+or-squre root of 1-sin squared(x) , pi/2<x<pi

    help would be much appreciated
    If you let u = 1-sin^2 (x) and use the chain rule in this format

    \displaystyle \frac{d \sqrt{u}}{du}\frac{du}{dx}
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