differentiate: y = x^ ½ (1 – 2x)^ 2/3 ÷ (2 – 3x)^ 3/4 (3 – 4x)^ 4/5 x^1/2 means x power 1/2 this is how i have started, but im stuck.. is this the right way of doing it?plz help me ln y = (½ ln x)(2/3 ln (1 – 2x)) – ¾ ln (2 -3x) 4/5 ln (3 -4x)
differentiate: y = x^ ½ (1 – 2x)^ 2/3 ÷ (2 – 3x)^ 3/4 (3 – 4x)^ 4/5 x^1/2 means x power 1/2 this is how i have started, but im stuck.. is this the right way of doing it?plz help me ln y = (½ ln x)(2/3 ln (1 – 2x)) – ¾ ln (2 -3x) 4/5 ln (3 -4x)
no. the problem is
[IMG]file:///C:/DOCUME%7E1/yajna10/LOCALS%7E1/Temp/moz-screenshot-2.jpg[/IMG] y = x^1/2(1-2x)^2/3 ÷ (2-3x)^3/4(3-4x)^4/5
sorry i made a mistake..
can i use ln first then differentiate..
can you show me how to do it plz??