Results 1 to 2 of 2

Math Help - Trapezium tank

  1. #1
    Newbie
    Joined
    May 2011
    Posts
    15

    Trapezium tank

    Hi

    ive had a problem to do of a trapezium tank

    using the area of a trapezium rule where a=w b=w-2x and h=(sqrt of 4xw-w^2)/2

    by substituting all the values in and simplifying the expression I finally end up with

    (w-x*(sqrt(4xw-w^w))/2

    Now i need to find the maximum volume the tank can hold which i know is to differentiate. Ive made a number of attempts but they are all dead ends. Please help
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    Joined
    Dec 2009
    From
    1111
    Posts
    872
    Thanks
    3
    Quote Originally Posted by nikki1234 View Post
    Hi

    ive had a problem to do of a trapezium tank

    using the area of a trapezium rule where a=w b=w-2x and h=(sqrt of 4xw-w^2)/2

    by substituting all the values in and simplifying the expression I finally end up with

    (w-x*(sqrt(4xw-w^w))/2

    Now i need to find the maximum volume the tank can hold which i know is to differentiate. Ive made a number of attempts but they are all dead ends. Please help
    Dear nikki1234,

    I think your question need a bit of clarification. What are a and b? I hope h is the height of the tank.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Trapezium Proof
    Posted in the Geometry Forum
    Replies: 4
    Last Post: January 16th 2011, 06:13 PM
  2. Trapezium
    Posted in the Geometry Forum
    Replies: 2
    Last Post: December 19th 2010, 01:42 PM
  3. Trapezium Rule
    Posted in the Calculus Forum
    Replies: 4
    Last Post: November 14th 2010, 11:24 AM
  4. trapezium
    Posted in the Geometry Forum
    Replies: 1
    Last Post: December 7th 2009, 03:24 AM
  5. Replies: 1
    Last Post: December 4th 2007, 04:45 PM

Search Tags


/mathhelpforum @mathhelpforum