can u explain to me a little bit more of this question...maybe can u show me some detailed working out i am still kinda confused
i just to do the integration of cos x - integration of 3/2pi x
both from zero to their intersection ...not sure if it is right~ but i found their intersection can not be expressed in fraction it looks like kind of irrational number
Sudharaka found the point of intersection in Post # 2. It is pi/3. So integrate the straight line from zero to the point of intersection, and then ADD the integral of cosine from the point of intersection to pi/2, where the cosine function hits the x-axis (equivalent to y = 0, which is one of the boundaries of your region). Does that make sense?
I think I need ur help now~
some one said there are actually two enclosed areas, by these 3 equations. One is from -pi/2 to pi/3 , and the other one is from 0 to pi/2 . I double checked the equation it said find the AREA bounded by the curves ,so it means there just one area right? I am confused now...
The area of region 1 is:
The area of region 2 is :
I think region 2 is right but i am not sure whether should i include the region 1 or not