1. divergent

Determine whether the improper integral converges or diverges. If it converges, find the value.

4e^4x at (-infinity. 0]

2. $\displaystyle\int_{-\infty}^04e^{4x}dx=\lim_{n\to\infty}\int_{-n}^04e^{4x}dx=\lim_{n\to\infty}\left(\left.e^{4x}\ right|_{-n}^0\right)=$
$\displaystyle =\lim_{n\to\infty}(1-e^{-4n})=1$