Volume calculation, function rotation around the x-axis.

Hello everyone.

I'm in need of some help with Volume calculations (with a function that is rotating around the x-axis).

I got stuck on the following: y = 3/sqrt{2-x} interval: -1 =< x =< 1

{1 {1

\pi \int y^2 = \pi \int 9/(2-x) = /pi [Need help with this bit]

{-1 {-1

I think my big problem is to find correct Antiderivative.

Did edit a little to make it more understandable.

Sorry but i dont understand how latex work (so it looks ugly i know) and the help page on this site doesn't work (Shake)

I would be very thankful if anyone with more insight than me could give me some help. Primarily with Antiderivative.

(Hi) Have a nice day