find dy/dx of sin(xy)=x+y
So far I have
cos(xy)*(xy'+1y)=1+y'
(cos(xy))xy'+(cos(xy))y=1+y'
Then, I'm sure you solve here for y but for the life of me I don't see the logical steps to get to y.
Would it be
y=((1+y')-(cos(xy)xy'))/(cos(xy))
???
find dy/dx of sin(xy)=x+y
So far I have
cos(xy)*(xy'+1y)=1+y'
(cos(xy))xy'+(cos(xy))y=1+y'
Then, I'm sure you solve here for y but for the life of me I don't see the logical steps to get to y.
Would it be
y=((1+y')-(cos(xy)xy'))/(cos(xy))
???