Just trying to verify my work.
Find dy/dx for y=sin^5(cos(cos(3x)))
dy/dx= 5(sin(cos(cos(3x))))^4 * cos(cos(3x)) * (-sin(3x)) * 3
Does this look right to you all?
dy/dx of y=sin^5(cos(cos3x)) which is also (sin(cos(cos(3x)))^5
Logically, we multiply the entire function by the exponent (5) and reduce it (the exponent) by 1.
y=5(sin^4(cos(cos(3x)))
Then we move along to the second layer (sin(cos(cos(3x))) which gives us
y=5(sin^4(cos(cos(3x))) * cos(cos(3x))
Then the third layer (cos(3x))
y=5(sin^4(cos(cos(3x))) * cos(cos(3x)) * (-sin(3x))
Then the fourth layer (3x)
y=5(sin^4(cos(cos(3x))) * cos(cos(3x)) * (-sin(3x)) * 3
It would help me greatly if you could point out the specific flaws in this logic. Thanks so much!
Take a look at this.
Be sure to ask it to show steps.
find dy/dx of sin^5(cos(3x))
I have, 5sin^4(cos(3x)) * cos(cos(3x)) * (-sin3x) * 3
Moderator edit: User made this correction to the original question that was asked.
It may look good to you, but it is wrong.
This is the correct answer.