Evaluate the iterated integral by converting to polar coordinates.
However, I'm not sure how you did that integration with respect to r, since requires a substitution..
Thanks for the response!
I know about that property, it has definitely saved me some headaches in the past!
I had originally integrated everything by hand, but I arrived at the incorrect end result several times (including this one). I decided to try to isolate my problem by using Wolfram Alpha to do my integration in an attempt to make sure at least the integration portion of the problem was correct.
The exact input string I used was,
int_0^3 (sin(r^2)*r) dr
Which returns .