Question:

Differentiate with respect to x:

Any help is thanked.

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- August 23rd 2007, 03:36 AMname101Differentiate Question
Question:

Differentiate with respect to x:

Any help is thanked. - August 23rd 2007, 05:34 AMnoreaction
I assume you learnt some differentiation.

Use the quotient rule:

when y = u/v

dy/dx = [v(du/dx) - u (dv/dx)] / v²

In your case y= (x+3)/(x-2) so

dy/dx = [(x-2)1 - (x+3)1] / (x-2)²

= (x-2-x-3)/ (x-2)²

= -5 / (x-2)²

I like to keep it in brackets, but you can expand if needed. - August 23rd 2007, 11:54 AMKrizalid