Hey everyone, just wondering whats the difference when I integrate:

$\displaystyle \int\dfrac{1}{-x+1}\,dx$

it be integrated in 2 ways

$\displaystyle -\int\dfrac{1}{x-1}=-ln(x-1)$

OR

$\displaystyle -\int\dfrac{-1}{-x+1}\,dx=-ln(-x+1)$

are those 2 solutions different? or is there some log manipulation to make

$\displaystyle -ln(x-1)\text{be the same as} -ln(-x+1)$