Please help, just can't remember how to do this! Differentiate 1/(1-x) (w.r.t.x) It's for part of a ridiculously hard stats problem, I just can't recall this simple rule! Thanks
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Rewrite it as (1 - x)^{-1} and then use the chain rule...
Originally Posted by canger Please help, just can't remember how to do this! Differentiate 1/(1-x) (w.r.t.x) It's for part of a ridiculously hard stats problem, I just can't recall this simple rule! Thanks Use Quotient rule $\displaystyle \displaystyle \frac{ vu' - uv'}{v^2}$ where u = 1 and v =(1-x) you should get 1/(1-x)^2
Ta!
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