Hi I am stuck with this problem. I do not know what and how to get ride of the Square Root. Dx ln sqrt(3x-2) How do I get rid of that? Also, Is there another way to write x(ln x)^2 in a more simplier term?
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Originally Posted by killasnake Hi I am stuck with this problem. I do not know what and how to get ride of the Square Root. Dx ln sqrt(3x-2) How do I get rid of that? Also, Is there another way to write x(ln x)^2 in a more simplier term? $\displaystyle \ln \sqrt{3x-2} = \ln (3x-2)^{1/2} = \frac{1}{2} \ln (3x-2)$
oh.... duh okay Thank you
Originally Posted by killasnake Is there another way to write x(ln x)^2 in a more simplier term? $\displaystyle x \left ( ln(x) \right )^2 = x \cdot ln^2(x)$ It's only a notational simplification. That's the best you can do. -Dan
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