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Math Help - implicit differentiation

  1. #1
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    implicit differentiation

    so I have x*y^2 + x*y = sin y and i try to solve for y'.
    So far I have x2yy' + y^2 + xy' + y = cosyy'.
    It looks as though as I am going to factor out the y' on the left side of the equation and then divide both side by y' but I am going to lose my y'??? I am a little stuck. any help or steps so a solution would be appreciated.
    -Marcus
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  2. #2
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    Move everything that has a y' term to one side, then factorise and divide by the other factor.
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  3. #3
    MHF Contributor FernandoRevilla's Avatar
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    Quote Originally Posted by mjfuentes85 View Post
    So far I have x2yy' + y^2 + xy' + y = cosyy'.

    Right, now

    y'=\dfrac{y^2+y}{\cos y-2xy-x}


    Edited: Sorry, I didn't see Prove It's post.
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  4. #4
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    can you show me the steps in between ?? I am missing the connection.

    Never mind I was completely missing that you I should subtract both sides by cosyy' then factor out the y'. Thnx guys for your help
    -Marcus
    Last edited by mjfuentes85; May 2nd 2011 at 12:06 AM.
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