Limit

**BAHADEEN** · April 29th 2011, 05:41 AM

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**Ackbeet** · April 29th 2011, 05:52 AM

What ideas have you had so far?

**BAHADEEN** · April 29th 2011, 06:34 AM

Originally Posted by Ackbeet

What ideas have you had so far?

I am trying to find the equation of the line that pass through (a/2 ,a^2/2) and (0,b)

**Ackbeet** · April 29th 2011, 06:37 AM

Originally Posted by BAHADEEN

I am trying to find the equation of the line that pass through (a/2 ,a^2/2) and (0,b)

Not a bad way to start, except that the line will go through $\left(\frac{a}{2},\frac{a^{2}}{4}\right)$ not $\left(\frac{a}{2},\frac{a^{2}}{2}\right).$ What do you get?

**BAHADEEN** · April 29th 2011, 06:52 AM

Originally Posted by Ackbeet

Not a bad way to start, except that the line will go through $\left(\frac{a}{2},\frac{a^{2}}{4}\right)$ not $\left(\frac{a}{2},\frac{a^{2}}{2}\right).$ What do you get?

i get y=(2a^2-8b/4a)x+b

**Ackbeet** · April 29th 2011, 07:01 AM

Originally Posted by BAHADEEN

i get y=(2a^2-8b/4a)x+b

I don't think you've quite got it yet. If you plug in $x=a/2,$ you don't get $y=a^{2}/4,$ like you should. Can you show your work?

**Plato** · April 29th 2011, 07:01 AM

Originally Posted by Ackbeet

Not a bad way to start, except that the line will go through $\left(\frac{a}{2},\frac{a^{2}}{4}\right)$ not $\left(\frac{a}{2},\frac{a^{2}}{2}\right).$ What do you get?

Actually it is $\left(\frac{a}{2},\frac{a^{2}}{2}\right).$ .
Because we want the midpoint of the line segment between $(0,0),~\&~(a,a^2)$ .

**Ackbeet** · April 29th 2011, 07:05 AM

Originally Posted by Plato

Actually it is $\left(\frac{a}{2},\frac{a^{2}}{2}\right).$ .
Because we want the midpoint of the line segment between $(0,0),~\&~(a,a^2)$ .

Ach! You're right. The midpoint should be on the line, not the function. BAHADEEN's line is still incorrect, though, because I get $a^{3}$ for y when I plug in $x=a/2$ .

Originally Posted by topsquark

Ack! Beet beat me again!

How about "Ack! Beet-red beat me again!"? Like Deveno, you could even put that in your signature if you wanted.

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