# Limit

• April 29th 2011, 05:41 AM
Limit
[IMG]www.0zz0.com]http://www6.0zz0.com/2011/04/29/13/285781234.gif[/url][/IMG]
• April 29th 2011, 05:52 AM
Ackbeet
What ideas have you had so far?
• April 29th 2011, 06:34 AM
Quote:

Originally Posted by Ackbeet
What ideas have you had so far?

I am trying to find the equation of the line that pass through (a/2 ,a^2/2) and (0,b)
• April 29th 2011, 06:37 AM
Ackbeet
Quote:

I am trying to find the equation of the line that pass through (a/2 ,a^2/2) and (0,b)

Not a bad way to start, except that the line will go through $\left(\frac{a}{2},\frac{a^{2}}{4}\right)$ not $\left(\frac{a}{2},\frac{a^{2}}{2}\right).$ What do you get?
• April 29th 2011, 06:52 AM
Quote:

Originally Posted by Ackbeet
Not a bad way to start, except that the line will go through $\left(\frac{a}{2},\frac{a^{2}}{4}\right)$ not $\left(\frac{a}{2},\frac{a^{2}}{2}\right).$ What do you get?

i get y=(2a^2-8b/4a)x+b
• April 29th 2011, 07:01 AM
Plato
Quote:

Originally Posted by Ackbeet
Not a bad way to start, except that the line will go through $\left(\frac{a}{2},\frac{a^{2}}{4}\right)$ not $\left(\frac{a}{2},\frac{a^{2}}{2}\right).$ What do you get?

Actually it is $\left(\frac{a}{2},\frac{a^{2}}{2}\right).$.
Because we want the midpoint of the line segment between $(0,0),~\&~(a,a^2)$.
• April 29th 2011, 07:01 AM
Ackbeet
Quote:

i get y=(2a^2-8b/4a)x+b

I don't think you've quite got it yet. If you plug in $x=a/2,$ you don't get $y=a^{2}/4,$ like you should. Can you show your work?
• April 29th 2011, 07:05 AM
Ackbeet
Quote:

Originally Posted by Plato
Actually it is $\left(\frac{a}{2},\frac{a^{2}}{2}\right).$.
Because we want the midpoint of the line segment between $(0,0),~\&~(a,a^2)$.

Ach! You're right. The midpoint should be on the line, not the function. BAHADEEN's line is still incorrect, though, because I get $a^{3}$ for y when I plug in $x=a/2$.

Quote:

Originally Posted by topsquark
Ack! Beet beat me again!

How about "Ack! Beet-red beat me again!"? Like Deveno, you could even put that in your signature if you wanted.