Hello, I am trying to understand how this was differentiated: 1/3x^3 I would have thought: -3x^-3 9x^-4 9/x^4 but I know this wrong. Can someone please point out where I am going wrong ? Thanks kindly.
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Originally Posted by fran1942 Hello, I am trying to understand how this was differentiated: 1/3x^3 I would have thought: -3x^-3 9x^-4 9/x^4 but I know this wrong. Can someone please point out where I am going wrong ? Thanks kindly. Is it 1/(3x^3) ?? Then it's (1/3)x^-3, the derivative is -3(1/3)x^-4 = -1x^-4 = -1/x^4
Originally Posted by fran1942 Hello, I am trying to understand how this was differentiated: 1/3x^3 I would have thought: -3x^-3 This is your mistake. [itex]1/3= 3^{-1}[/itex], not [itex]-3[/itex] 9x^-4 9/x^4 but I know this wrong. Can someone please point out where I am going wrong ? Thanks kindly.[/QUOTE]
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