\int 2^3ln(x)dx

What I did:

u = ln(x) v = 2x^4/4

du = 1/x dv = 2x^3*dx

Then it becomes: \int ln(x)(2x^4/4) - \int (2x^4/4x)

Next from \int (2x^4/4x)

u = 1/x v = x^5/10

du = -1/x^2 dv = 2x^4/4

Thus becoming: (1/x)(2x^4/4)dx - \int x^5/10(-1/x^2)

At this point it does not seem to be right because my teachers answer is x^4/(4ln(x) - 1)

Can someone help me please? I have a test tomorrow and I need to know ASAP.