Your u du v and dv are all correct
Remember the formula for integration by parts is
So plugging in your info above I get
You do not need integration by parts just use the power rule!
\int 2^3ln(x)dx
What I did:
u = ln(x) v = 2x^4/4
du = 1/x dv = 2x^3*dx
Then it becomes: \int ln(x)(2x^4/4) - \int (2x^4/4x)
Next from \int (2x^4/4x)
u = 1/x v = x^5/10
du = -1/x^2 dv = 2x^4/4
Thus becoming: (1/x)(2x^4/4)dx - \int x^5/10(-1/x^2)
At this point it does not seem to be right because my teachers answer is x^4/(4ln(x) - 1)
Can someone help me please? I have a test tomorrow and I need to know ASAP.