$\displaystyle \iiint $$\displaystyle \sqrt{x^2+y^2+z^2} $

1st integral is 0 to $\displaystyle \sqrt{1 -x^2 -y^2} $ (innermost)

2nd integral is 0 to $\displaystyle \sqrt{1-x^2} $

3rd integral is 0 to 1 (outermost)

plse help me out

having trouble inputing question hope this is clear

i am having trouble converting this rectangular triple integral to spherical integrals