Thread: Area of a shaded region (analytically)

I'm having a little trouble with (the circled) number 2 on this scan:

As far as I know it's: Integrated from -\pi/3 to \pi/3
So, would you not minus the top function from the bottom, find the anti-derivative and substitute in b and a?

Originally Posted by Attenel

I'm having a little trouble with (the circled) number 2 on this scan:

As far as I know it's: Integrated from -\pi/3 to \pi/3
So, would you not minus the top function from the bottom, find the anti-derivative and substitute in b and a?

since the integral of the bottom function will come out to be negative i would subtract the integral of bottom function from the integral of top function.