one more guys please

differentiate using the prduct rule

$\displaystyle

y(x) = (5x^3 + 8x^2 - 2x + 1)e^x

$

$\displaystyle

u = (5x^3 + 8x^2 - 2x + 1) v = e^x

$

$\displaystyle

\frac{du}{dx}= (10x^2 + 16x - 2)

$

so

$\displaystyle

\frac{dy}{dx}= v\frac{du}{dx} + u\frac{dv}{dx} = e^x(10x^2 + 16x - 2) + (5x^3 + 8x^2 - 2x + 1)e^x

$