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Math Help - Differentiation

  1. #1
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    Differentiation

    Hey guys could you just check if i did this right please?

    q: Differentiate using the chain rule

    a:
    <br />
y(x) = cos(5x^2+8)<br />

    <br />
u = (5x^2+8)<br />

    <br />
du/dx = 10x<br />

    <br />
dy/du = -sin(u)<br />

    <br />
dy/dx = -sin(10x)<br />
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by mxmadman_44 View Post
    Hey guys could you just check if i did this right please?

    q: Differentiate using the chain rule

    a:
    <br />
y(x) = cos(5x^2+8)<br />

    <br />
u = (5x^2+8)<br />

    <br />
du/dx = 10x<br />

    <br />
dy/du = -sin(u)<br />

    <br />
dy/dx = -sin(10x)<br />
    <br />
\frac{dy}{dx}=\frac{dy}{du}\frac{du}{dx}=[-sin(5x^2+8)][10x]<br />

    RonL
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  3. #3
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    Quote Originally Posted by mxmadman_44 View Post
    Hey guys could you just check if i did this right please?

    q: Differentiate using the chain rule

    a:
    <br />
y(x) = cos(5x^2+8)<br />

    <br />
u = (5x^2+8)<br />

    <br />
du/dx = 10x<br />

    <br />
dy/du = -sin(u)<br />

    <br />
dy/dx = -sin(10x)<br />
    Hello,

    <br />
dy/du = -sin(u) here you have to re-substitute:
    <br />
dy/dx = -sin(5x^2+8) \cdot (10x)
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  4. #4
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    thanks

    thanks guys
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