1. ## Evaluating a limit

I'm not sure how to calculate the following

lim(z tends to -i) (z^2-iz)/(2z^2+2)

2. Why not try L'Hopital's Rule?

3. Originally Posted by joesmith
I'm not sure how to calculate the following

lim(z tends to -i) (z^2-iz)/(2z^2+2)
You can consider that is...

(1)

... and from (1) is easy to see that the limit z tends -i doesn't exist...

Kind regards

$\chi$ $\sigma$