dont be scared look at it from mathematical point of view
i just want to understand how they transform the painting to the integral
cant understand what is ds
and why it equals rd(phy)
maybe the confused phu with teta(cause i dont see phi)
i still cant see what that means
?
i got a bowl spinning arround the Z axes with omega angular velocity
the bowl is charged with sigma charge density
i need to find out what is the magnetic feild in every point in the "z" axes
??
does it change some how your answer?
you are saying ds is a wire without width??
so ds is just a peace of line (its no a circle?)
having no width is a problem because we need to integrate from the start of the bowl till the top
and not having any width element doesnt give me the dx element in the integral
yess that exactly what thought to do
the physics part here is is automatic just put in the formua
the hard part is geometry
i did a sctech
k is the constant part(tired to write the constants all the time )
the formula is dB=
d=
alpha is the angle between dl and the direction of we point we want to find the magnetic feild it
my latex doesnt compile dB=\frac{kIsin(\theta)dl}{d^2}
d=\sqrt{r^2+z^2}
and i dont know how to find dI??
I=integral of Jda
they did some thing different
i dont understand that
so it make sense do do what the original photo did
but idont understand the geometry
of how they get ds
and actually see it in the picture
and how they integrate
the formula is for dl??? (thin wire) thats the problem
we want to integrate by strips